Solve for \( x \). \[ \begin{array}{l}5^{(6 x-1)}=5^{(4 x+3)} \\ \text { A. } x=\frac{1}{2} \\ \text { B. } x=5 \\ \text { D. } x=2 \\ \text { D. } x=\frac{1}{5}\end{array} \]

To solve the equation \( 5^{(6x-1)} = 5^{(4x+3)} \), we can set the exponents equal to each other since the bases are the same: \[ 6x - 1 = 4x + 3 \] Next, we will isolate \( x \): 1. Subtract \( 4x \) from both sides: \[ 6x - 4x - 1 = 3 \] which simplifies to \[ 2x - 1 = 3 \] 2. Add 1 to both sides: \[ 2x = 4 \] 3. Finally, divide by 2: \[ x = 2 \] So, the solution is \( x = 2 \). Thus, the answer is \( \text{D. } x = 2 \).