Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra \( \$ 23,000 \) over the next 6 years. What amount must be deposited quarterly into an account that earns \( 5.9 \% \) interest, compounded quarterly, in order to reach your goal? Round your answer to the nearest cent, if necessary. Formuia
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To find the amount that must be deposited quarterly, you can use the future value of an ordinary annuity formula, which is: \[ FV = P \times \left(\frac{(1 + r/n)^{nt} - 1}{r/n}\right) \] Where: - \( FV \) is the future value (the amount you want to save, \( \$23,000 \)), - \( P \) is the payment (the amount to be deposited quarterly), - \( r \) is the annual interest rate (5.9% or 0.059), - \( n \) is the number of compounding periods per year (4 for quarterly), - \( t \) is the number of years (6). Rearranging the formula to solve for \( P \): \[ P = \frac{FV}{\left(\frac{(1 + r/n)^{nt} - 1}{r/n}\right)} \] Now, plug in the values: - \( FV = 23000 \) - \( r = 0.059 \) - \( n = 4 \) - \( t = 6 \) Calculate \( P \): 1. Calculate \( r/n \): \[ r/n = 0.059/4 = 0.01475 \] 2. Calculate \( nt \): \[ nt = 4 \times 6 = 24 \] 3. Calculate \( (1 + r/n)^{nt} \): \[ (1 + 0.01475)^{24} \approx 1.4082 \] 4. Now calculate the full formula: \[ \frac{(1.4082 - 1)}{0.01475} \approx 27.5584 \] 5. Finally, solve for \( P \): \[ P = \frac{23000}{27.5584} \approx 834.14 \] So, you need to deposit approximately \( \$834.14 \) quarterly to reach your goal of \( \$23,000 \) in 6 years!