Multiply $$ (x-3)(4 x+2) $$ using the distributive property. Select the answer choice showing the correct distribution. A. $$ (x-3)(4 x)+(4 x)(2) $$ B. $$ (x)(4 x)+2(x)+4 x+2 $$ C. $$ (x)(4 x+2)+(x-3) $$ D. $$ (x-3)(4 x)+(x-3)(2) $$

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To correctly multiply $$ (x - 3)(4x + 2) $$ using the distributive property, you need to distribute each term in the first binomial $$ (x - 3) $$ to each term in the second binomial $$ (4x + 2) $$. This involves two separate distributions:

1. **Distribute $$ (x - 3) $$ to $$ 4x $$:**
   $$
   (x - 3)(4x) = x \cdot 4x + (-3) \cdot 4x = 4x^2 - 12x
   $$

2. **Distribute $$ (x - 3) $$ to $$ 2 $$:**
   $$
   (x - 3)(2) = x \cdot 2 + (-3) \cdot 2 = 2x - 6
   $$

Putting it all together:
$$
(x - 3)(4x + 2) = (x - 3)(4x) + (x - 3)(2)
$$

**Answer Choice D** accurately represents this distribution:
$$
\boxed{ \text{D.} \ (x-3)(4 x)+(x-3)(2) }
$$
The correct distribution is $$ (x-3)(4x) + (x-3)(2) $$, which is choice D.

Multiply \( (x-3)(4 x+2) \) using the distributive property. Select the answer choice showing the correct distribution. A. \( (x-3)(4 x)+(4 x)(2) \) B. \( (x)(4 x)+2(x)+4 x+2 \) C. \( (x)(4 x+2)+(x-3) \) D. \( (x-3)(4 x)+(x-3)(2) \)

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