Part 3 of 7 \( \bigcirc \) Points: 0 of 2 Use the given function to complete parts (a) through (e) below \[ f(x)=x^{4}-9 x^{2} \] a) Use the Leading Coefficient Test to determine the graph's end behavior A. The graph of \( f(x) \) rises left and falls night B The graph of \( f(x) \) nises left and rises right C. The graph of \( f(x) \) falls left and falls night D. The graph of \( f(x) \) falls left and nses right b) Find the \( x \)-intercepts. \[ x=0,3,-3 \] (Type an integer or a decimal Usent comma to separate answers as needed) At which zeros does the graph of the function cross the \( x \)-axis? Select the correct choice below and, if necessary. fill in the answer box to complete your choice A. \( x= \) \( \square \) (Type an integer or a decimal Use a comma to separate answers as needed) B. There are no \( x \)-intercepts at which the graph crosses the \( x \)-axis
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The Deep Dive
The Leading Coefficient Test signifies that as \( x \) approaches positive or negative infinity, the end behavior of the polynomial function can be understood by looking at the leading term. Given that the leading term is \( x^4 \) with a positive coefficient, the function rises on both ends. So, the correct answer is B: The graph of \( f(x) \) rises left and rises right. When it comes to the \( x \)-intercepts of the function \( f(x)=x^{4}-9x^{2} \), we can find them by solving \( f(x) = 0 \). Factoring out \( x^2 \) gives us \( x^2(x^2 - 9) = 0 \), leading to the intercepts at \( x = 0, 3, -3 \). The graph crosses the \( x \)-axis at all these points because each factor corresponds to simple roots. Therefore, the answer for where the graph crosses the \( x \)-axis is A: \( x = 0, 3, -3 \).