\begin{tabular}{l} ype your answer \\ If a 737 takes off at an \( 8^{\circ} \) angle going 160 mph , at \\ what gradient is the plane climbing? Give your \\ answer as a percentage. (Note: \( \sin \left(8^{\circ}\right) \approx 0.14 \), \\ \( \left.\cos \left(8^{\circ}\right) \approx 0.99, \tan \left(8^{\circ}\right) \approx 0.14\right) \) \\ \hline\end{tabular}

To find the gradient, we can start with the tangent of the angle, which gives us the ratio of the vertical rise to the horizontal run. Since the angle is \(8^{\circ}\) and \(\tan(8^{\circ}) \approx 0.14\), this means that for every unit of horizontal distance, the plane rises approximately 0.14 units vertically. To express this as a percentage, we multiply by 100. Therefore, the gradient is \(0.14 \times 100 = 14\%\). If you're calculating angles for planes and other objects, make sure to also consider how altitude and distance can affect your calculations. A common mistake is overlooking the effect of wind resistance or curvature of the earth, especially at high trajectories! So always double-check your environmental factors as they may influence the actual outcome!