\( 2 x^{2}-7 x+c=(2 x-3)(x-2) \), then \( c= \)

To find \( c \), let's start by expanding the right side of the equation: \[ (2x-3)(x-2) = 2x \cdot x + 2x \cdot (-2) - 3 \cdot x - 3 \cdot (-2) \] \[ = 2x^2 - 4x - 3x + 6 = 2x^2 - 7x + 6 \] Now, we compare this with the left side of the equation: \[ 2x^2 - 7x + c \] From both expressions, we can see that the coefficients of \( x^2 \) and \( x \) match, thus: \[ c = 6 \] Therefore, the value of \( c \) is \( 6 \).