Pregunta
14. Which two expressions are equivalent? A. \( 7(3+x) \) and \( 7 \cdot 3+3 \cdot x \) B. \( 7+3+x \) and \( (7+3)+x \) C. \( 7 \cdot x \cdot 3 \) and \( 7(x+3) \) D. \( 7 \div(3-x) \) and \( 7 \div(x-3) \)
Ask by Peterson Munoz. in the United States
Jan 23,2025
Solución de tutoría real
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Option B contains two equivalent expressions.
Solución
Let's evaluate each pair of expressions to determine which ones are equivalent:
**A. \( 7(3+x) \) and \( 7 \cdot 3 + 3 \cdot x \)**
- **First Expression:** \( 7(3 + x) = 21 + 7x \)
- **Second Expression:** \( 7 \cdot 3 + 3 \cdot x = 21 + 3x \)
- **Conclusion:** These expressions are **not equivalent** because \( 7x \neq 3x \).
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**B. \( 7 + 3 + x \) and \( (7 + 3) + x \)**
- **First Expression:** \( 7 + 3 + x = 10 + x \)
- **Second Expression:** \( (7 + 3) + x = 10 + x \)
- **Conclusion:** These expressions are **equivalent**.
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**C. \( 7 \cdot x \cdot 3 \) and \( 7(x + 3) \)**
- **First Expression:** \( 7 \cdot x \cdot 3 = 21x \)
- **Second Expression:** \( 7(x + 3) = 7x + 21 \)
- **Conclusion:** These expressions are **not equivalent** because \( 21x \neq 7x + 21 \).
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**D. \( 7 \div (3 - x) \) and \( 7 \div (x - 3) \)**
- **First Expression:** \( \frac{7}{3 - x} \)
- **Second Expression:** \( \frac{7}{x - 3} \)
- **Conclusion:** These expressions are **not equivalent** because \( \frac{7}{3 - x} = -\frac{7}{x - 3} \).
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**Final Answer:**
**Option B** contains two equivalent expressions.
**Answer:**
**Option B** contains two equivalent expressions.
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Mind Expander
Alright, let’s break it down! The first expression that stands out is option A: \( 7(3+x) \) expands to \( 7 \cdot 3 + 7 \cdot x \) according to the distributive property. So yes, they are equivalent! On to the second one, if we look at option B: \( 7 + 3 + x \) is associative, meaning it doesn't matter how we group the numbers; \((7 + 3) + x\) is the same as \(7 + 3 + x\). They are also equivalent! So, the equivalent expressions are A and B! Keep cracking those equations!
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