Euler's formula, $$ V-E+F=2 $$ relates the number of vertices $$ V $$, the number of edges $$ E $$, and the number of faces $$ F $$ of a polyhedron. How many faces does a polyhedron with 4 vertices and 6 edges have? 6 4 7

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$$
\textbf{Passo 1:} \text{Utilizamos a fórmula de Euler: } V - E + F = 2.
$$

$$
\textbf{Passo 2:} \text{Substituímos } V = 4 \text{ e } E = 6 \text{ na fórmula: } 4 - 6 + F = 2.
$$

$$
\textbf{Passo 3:} \text{Simplificamos a equação: } -2 + F = 2.
$$

$$
\textbf{Passo 4:} \text{Para encontrar } F, \text{ somamos } 2 \text{ em ambos os lados: } F = 2 + 2 = 4.
$$

Resposta: $$ 4 $$ faces.
A poliedro tem 4 faces.

Euler’s formula, relates the number of vertices , the number of edges , and the number of faces of a polyhedron. How many faces does a
polyhedron with 4 vertices and 6 edges have?
6
4
7

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Euler’s formula, relates the number of vertices , the number of edges , and the number of faces of a polyhedron. How many faces does a polyhedron with 4 vertices and 6 edges have? 6 4 7