Pregunta
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Marcus and his friends have \( \$ 125 \) to spend on tickets and food at a movie theater. If the cost of the tickets is more than \( \$ 75 \), which inequality represents the dollar amount, \( f \) Marcus can spend on food? A) \( f>50 \) C) \( f>200 \) B) \( f<50 \) D) \( f<200 \) Untitled Question * 1 point A) \( f>50 \) B) f \( <50 \) C) \( f>200 \) D) \( f<200 \)

Ask by Marsh Warner. in the United States
Jan 23,2025

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The correct inequality is \( f < 50 \).

Solución

To determine the appropriate inequality for the amount \( f \) Marcus can spend on food, let's break it down: 1. **Total Budget:** \( \$125 \) 2. **Cost of Tickets:** More than \( \$75 \), so \( \text{Tickets} > \$75 \) Since the total amount spent on tickets and food cannot exceed \( \$125 \), we can set up the following inequality: \[ \text{Tickets} + f \leq 125 \] Given that the cost of tickets is more than \( \$75 \): \[ f \leq 125 - 75 \] \[ f \leq 50 \] However, since the cost of tickets is *greater than* \( \$75 \), the amount spent on food \( f \) must be *less than* \( \$50 \). Therefore, the correct inequality is: **B) \( f < 50 \)**

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Mind Expander

If the cost of the tickets is more than \( \$ 75 \), that means the remaining amount for food would be less than \( \$ 50 \), since Marcus and his friends have \( \$ 125 \) in total. This results in the inequality \( f < 50 \). Therefore, the correct answer is B) \( f < 50 \). Now, let's make this a bit more intriguing: Did you know that budgeting for a fun day out like a movie is a skill that can help cultivate smart financial habits for life? Understanding how to allocate your funds, whether for entertainment or essentials, can set a solid foundation for personal finance! For a fun challenge, try creating a budget for a hypothetical night out! List down ticket prices, food choices, and any extras like snacks or drinks. You can play around with different total amounts to see how your choices affect your budget. This can be a delightful way to practice math while planning a memorable outing!

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