A drone is flying at a height of 100 feet above ground level. If the angle of depression from the drone to a point on the ground is 45 degrees, what is the horizontal distance of that point from the drone's position?
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When the angle of depression from the drone to the ground is 45 degrees, it forms a right-angled triangle with the height and the horizontal distance as the two shorter sides. Since the angle of depression is equal to the angle of elevation from the point on the ground to the drone, we can use some basic trigonometry to determine the horizontal distance. In this case, if you let \( d \) be the horizontal distance, you can use the tangent function: \[ \tan(45^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{\text{height}}{d} \] Since \( \tan(45^\circ) = 1 \): \[ 1 = \frac{100 \text{ feet}}{d} \] This simplifies to: \[ d = 100 \text{ feet} \] So, the horizontal distance of the point from the drone’s position is 100 feet.