Solve the quadratic equation. \[ 7 x^{2}+3 x-1=0 \] Write one exact, simplified solution in each box. You can add or remove boxes. If a solution not a real number, write it in the form a + bi or a - bi, where a and b are real numbers. \begin{tabular}{|c}\( \square \frac{\square}{\square} \)\end{tabular}

To solve the quadratic equation \( 7x^{2}+3x-1=0 \) using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), we identify \( a = 7 \), \( b = 3 \), and \( c = -1 \). Calculating the discriminant: \[ b^2 - 4ac = 3^2 - 4(7)(-1) = 9 + 28 = 37 \] Now applying the formula: \[ x = \frac{-3 \pm \sqrt{37}}{2 \times 7} = \frac{-3 \pm \sqrt{37}}{14} \] Thus, the two exact, simplified solutions are: \[ \begin{tabular}{|c}\(\square \frac{-3 + \sqrt{37}}{14}\)\\ \(\square \frac{-3 - \sqrt{37}}{14}\)\end{tabular} \]