4. \( 2+3 \times(8-4) \div 6 \)

To solve the expression \( 2+3 \times(8-4) \div 6 \), we start by evaluating the parentheses: \( 8-4 = 4 \). Now the expression becomes \( 2 + 3 \times 4 \div 6 \). Following the order of operations (multiplication and division from left to right), we calculate \( 3 \times 4 = 12 \), giving us \( 2 + 12 \div 6 \). Next, we divide: \( 12 \div 6 = 2 \). Finally, we sum \( 2 + 2 = 4 \). Thus, the final answer is \( 4 \).