Karen's car weighs \( 6 \frac{3}{8} \) tons and Ava's car weighs \( 4 \frac{1}{8} \) tons. How much more does Karen's car weigh than Ava's car?

To find out how much more Karen's car weighs than Ava's, we need to subtract Ava's car weight from Karen's car weight. First, convert the mixed numbers to improper fractions: - Karen's car: \( 6 \frac{3}{8} = \frac{6 \cdot 8 + 3}{8} = \frac{48 + 3}{8} = \frac{51}{8} \) - Ava's car: \( 4 \frac{1}{8} = \frac{4 \cdot 8 + 1}{8} = \frac{32 + 1}{8} = \frac{33}{8} \) Now, subtract Ava's weight from Karen's weight: \[ \frac{51}{8} - \frac{33}{8} = \frac{51 - 33}{8} = \frac{18}{8} = \frac{9}{4} \text{ tons} \] Convert \(\frac{9}{4}\) to a mixed number: \(\frac{9}{4} = 2 \frac{1}{4}\) Therefore, Karen's car weighs \( 2 \frac{1}{4} \) tons more than Ava's car.