Pregunta
Simplify. \( \left.\qquad 5 x y^{2}+x^{2} y^{2}-7\right)-\left(2 x^{2} y-6\right) \) \( \square] \)\( \square^{\square} \)
Ask by Gough Lane. in the United States
Jan 27,2025
Solución de tutoría real
Respuesta verificada por el tutor
Responder
Simplify the expression to \(5xy^{2}+x^{2}y^{2}-2x^{2}y-1\).
Solución
Calculate or simplify the expression \( 5xy^{2}+x^{2}y^{2}-7-2x^{2}y+6 \).
Simplify the expression by following steps:
- step0: Solution:
\(5xy^{2}+x^{2}y^{2}-7-2x^{2}y+6\)
- step1: Add the numbers:
\(5xy^{2}+x^{2}y^{2}-1-2x^{2}y\)
The simplified expression is \(5xy^{2}+x^{2}y^{2}-1-2x^{2}y\).
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Bonus Knowledge
To simplify the expression \( (5xy^{2} + x^{2}y^{2} - 7) - (2x^{2}y - 6) \), we first distribute the negative sign across the second set of parentheses: \[ 5xy^{2} + x^{2}y^{2} - 7 - 2x^{2}y + 6. \] Now, combine like terms. The constant terms are \(-7 + 6 = -1\). There are no like terms for \(5xy^{2}\), \(x^{2}y^{2}\), and \(-2x^{2}y\). So we rewrite the expression: \[ 5xy^{2} + x^{2}y^{2} - 2x^{2}y - 1. \] Thus, the simplified result is: \[ 5xy^{2} + x^{2}y^{2} - 2x^{2}y - 1. \]
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