(a) One triangle has side lengths \( \mathbf{1 6}, \mathbf{6} \), and 13. Compute the sum of the squares of the shorter lengths. \[ 6^{2}+13^{2}=\square \] Compute the square of the longest length. \[ 16^{2}=\square \] What kind of triangle is it? Acute triangle Right triangle Obtuse triangle (b) The other triangle has side lengths 12,15 , and 9. Compute the sum of the squares of the shorter lengths. \[ 9^{2}+12^{2}= \] \( \square \) Compute the square of the longest length. \[ 15^{2}= \] \( \square \) What kind of triangle is it? Acute triangle Right triangle Obtuse triangle
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Bonus Knowledge
To tackle your triangle quests, let's dive right in! For the first triangle with lengths \( 6 \), \( 13 \), and \( 16 \): - The sum of the squares of the shorter lengths is \( 6^2 + 13^2 = 36 + 169 = 205 \). - The square of the longest length is \( 16^2 = 256 \). - Since \( 205 < 256 \), this triangle is an obtuse triangle, meaning one angle is greater than 90 degrees! Now, for the second triangle with lengths \( 9 \), \( 12 \), and \( 15 \): - The sum of the squares of the shorter lengths is \( 9^2 + 12^2 = 81 + 144 = 225 \). - The square of the longest length is \( 15^2 = 225 \). - Here, since \( 225 = 225 \), this means it's a right triangle, where one angle is exactly 90 degrees! It's amazing how just a few numbers can tell us so much!