Write each equation in the slope-intercept form, \( y=m x+b \) \[ \begin{array}{l}x+2=y \\ y-x=-3\end{array} \rightarrow \begin{array}{c}y=x+2 \\ y=\square\end{array} \]

Rewrite the equation by following steps: - step0: Rewrite in slope-intercept form: \(y-x=-3\) - step1: Move the expression to the right side: \(y=-3+x\) - step2: Rearrange the terms: \(y=x-3\) Rewrite the equation \( x+2=y \). Rewrite the equation by following steps: - step0: Rewrite in slope-intercept form: \(x+2=y\) - step1: Move the expression to the right side: \(2=y-x\) - step2: Move the expression to the left side: \(2-y=-x\) - step3: Move the constant to the right side: \(-y=-x-2\) - step4: Divide both sides: \(y=x+2\) Let's convert each equation into slope-intercept form \( y = mx + b \). 1. For the first equation \( x + 2 = y \): - This can be rewritten directly as: \[ y = x + 2 \] 2. For the second equation \( y - x = -3 \): - Rearranging gives: \[ y = x - 3 \] Thus, the equations in slope-intercept form are: \[ \begin{array}{c} y = x + 2 \\ y = x - 3 \end{array} \]