11. Suzy spent \( 6 \frac{7}{8} \) days working on her English paper, \( 3 \frac{1}{6} \) days doing her science project, and \( 1 \frac{1}{2} \) days studying for her math test. How many more days did Suzy spend on her English paper and math test combined than on her science project?
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To find out how many more days Suzy spent on her English paper and math test combined than on her science project, we first need to add the days for her English paper and math test together. Suzy spent: - \( 6 \frac{7}{8} \) days on her English paper - \( 1 \frac{1}{2} \) days on her math test Let's convert these mixed numbers to improper fractions: - \( 6 \frac{7}{8} = \frac{6 \times 8 + 7}{8} = \frac{48 + 7}{8} = \frac{55}{8} \) - \( 1 \frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2} = \frac{12}{8} \) (when converted to an equivalent fraction with a denominator of 8) Now, we can add these two values together: \[ \frac{55}{8} + \frac{12}{8} = \frac{55 + 12}{8} = \frac{67}{8} \] Next, let's convert her science project time to an improper fraction: - \( 3 \frac{1}{6} = \frac{3 \times 6 + 1}{6} = \frac{18 + 1}{6} = \frac{19}{6} \) To compare these, we will need a common denominator. The least common multiple of 8 and 6 is 24. Now, let's convert both fractions: \[ \frac{67}{8} = \frac{67 \times 3}{8 \times 3} = \frac{201}{24} \] \[ \frac{19}{6} = \frac{19 \times 4}{6 \times 4} = \frac{76}{24} \] Now, we subtract the days spent on her science project from the days spent on her English paper and math test combined: \[ \frac{201}{24} - \frac{76}{24} = \frac{201 - 76}{24} = \frac{125}{24} \] To express this in mixed number form: \[ 125 \div 24 = 5 \quad \text{remainder } 5 \] Thus, \( \frac{125}{24} = 5 \frac{5}{24} \) So, Suzy spent \( 5 \frac{5}{24} \) more days on her English paper and math test combined than on her science project.