Solve the equation. \( 8(4 x+8)=11-(x+2) \)

To solve the equation: \[ 8(4x + 8) = 11 - (x + 2) \] **Step 1: Expand both sides** First, distribute the multiplication on the left side and simplify the right side: \[ 8 \times 4x + 8 \times 8 = 11 - x - 2 \] \[ 32x + 64 = 9 - x \] **Step 2: Move all \(x\) terms to one side and constant terms to the other** Add \(x\) to both sides to get all \(x\) terms on the left: \[ 32x + x + 64 = 9 \] \[ 33x + 64 = 9 \] Subtract 64 from both sides to isolate the \(x\) term: \[ 33x = 9 - 64 \] \[ 33x = -55 \] **Step 3: Solve for \(x\)** Divide both sides by 33: \[ x = \frac{-55}{33} \] Simplify the fraction by dividing numerator and denominator by 11: \[ x = \frac{-5}{3} \] **Final Answer:** \[ x = -\frac{5}{3} \]