\( 25 a + 10 c - 5 = 25 ( \square \square ) + 10 ( \square \square ) - 5 \)

To solve the equation \[ 25 a + 10 c - 5 = 25 ( \square \square ) + 10 ( \square \square ) - 5, \] we can start by simplifying both sides. 1. **Identify the structure of the equation**: The left side is \(25a + 10c - 5\) and the right side has a similar structure with placeholders. 2. **Set the equation without the constant**: We can ignore the \(-5\) on both sides for now, leading to: \[ 25a + 10c = 25 ( \square \square ) + 10 ( \square \square ). \] 3. **Factor out common terms**: We can factor out \(25\) and \(10\) from both sides: \[ 25a + 10c = 25x + 10y, \] where \(x\) and \(y\) are the values that will replace the squares. 4. **Equate coefficients**: This gives us two equations: \[ 25a = 25x \quad \text{and} \quad 10c = 10y. \] 5. **Solve for \(x\) and \(y\)**: From \(25a = 25x\), we can divide both sides by \(25\): \[ a = x. \] From \(10c = 10y\), we can divide both sides by \(10\): \[ c = y. \] Thus, we can conclude that: \[ \boxed{(a, c)}. \] This means that the values that replace the squares are \(a\) and \(c\) respectively.