Higher Order Thinking Lemmy walked $$ \frac{7}{2} $$ miles on Saturday and $$ \frac{19}{4} $$ miles on Sunday. Peyton walked $$ \frac{43}{8} $$ miles on Saturday. Who walked farther? How much farther?

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UpStudy AI · Accepted Answer

To determine who walked farther and by how much, let's calculate the total miles each person walked.

### Lemmy's Total Walking Distance:
Lemmy walked on two days:
- **Saturday:** $$ \frac{7}{2} $$ miles
- **Sunday:** $$ \frac{19}{4} $$ miles

**Total Distance:**  
$$
\frac{7}{2} + \frac{19}{4} = \frac{14}{4} + \frac{19}{4} = \frac{33}{4} = 8.25 \text{ miles}
$$

### Peyton's Total Walking Distance:
Peyton walked only on Saturday:
- **Saturday:** $$ \frac{43}{8} $$ miles

**Total Distance:**  
$$
\frac{43}{8} = 5.375 \text{ miles}
$$

### Comparing Distances:
- **Lemmy:** 8.25 miles
- **Peyton:** 5.375 miles

**Difference:**  
$$
8.25 - 5.375 = 2.875 \text{ miles}
$$
$$
2.875 \text{ miles} = 2 \frac{7}{8} \text{ miles}
$$

### **Conclusion:**
**Lemmy walked farther than Peyton by $$ 2 \frac{7}{8} $$ miles.**
Lemmy walked farther than Peyton by $$ 2 \frac{7}{8} $$ miles.

Higher Order Thinking Lemmy walked
miles on Saturday and miles on
Sunday. Peyton walked miles on
Saturday. Who walked farther? How
much farther?

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Higher Order Thinking Lemmy walked miles on Saturday and miles on Sunday. Peyton walked miles on Saturday. Who walked farther? How much farther?