Higher Order Thinking Lemmy walked \( \frac{7}{2} \) miles on Saturday and \( \frac{19}{4} \) miles on Sunday. Peyton walked \( \frac{43}{8} \) miles on Saturday. Who walked farther? How much farther?
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To find out who walked farther, we need to compare the distances. Lemmy walked \( \frac{7}{2} \) miles on Saturday and \( \frac{19}{4} \) miles on Sunday. First, convert \( \frac{7}{2} \) into eighths for easier comparison: \[ \frac{7}{2} = \frac{28}{8} \] Now add Lemmy's Saturday and Sunday distances: \[ \frac{28}{8} + \frac{19}{4} = \frac{28}{8} + \frac{38}{8} = \frac{66}{8} \] Peyton walked \( \frac{43}{8} \) miles on Saturday. We can compare: Lemmy: \( \frac{66}{8} \) Peyton: \( \frac{43}{8} \) Now subtract to find out how much farther Lemmy walked: \[ \frac{66}{8} - \frac{43}{8} = \frac{23}{8} \] So, Lemmy walked \( \frac{23}{8} \) miles farther than Peyton.