4. Carolyn could walk 10 miles in 3 hours. (a) What was her speed? (b) How long would it take her to walk 25 miles at the same speat

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Let's solve each part of the problem step by step.

### Problem 4:
**Carolyn could walk 10 miles in 3 hours.**

#### (a) What was her speed?

**Solution:**

To find speed, use the formula:

$$
\text{Speed} = \frac{\text{Distance}}{\text{Time}}
$$

Given:
- **Distance** = 10 miles
- **Time** = 3 hours

Plugging in the values:

$$
\text{Speed} = \frac{10 \text{ miles}}{3 \text{ hours}} = \frac{10}{3} \text{ miles per hour} \approx 3.\overline{3} \text{ mph}
$$

**Answer:**  
Carolyn's speed was $$ \frac{10}{3} $$ miles per hour, which is approximately **3.33 mph**.

---

#### (b) How long would it take her to walk 25 miles at the same speed?

**Solution:**

To find time, use the formula:

$$
\text{Time} = \frac{\text{Distance}}{\text{Speed}}
$$

Given:
- **Distance** = 25 miles
- **Speed** = $$ \frac{10}{3} $$ mph

Plugging in the values:

$$
\text{Time} = \frac{25 \text{ miles}}{\frac{10}{3} \text{ mph}} = 25 \times \frac{3}{10} = \frac{75}{10} = 7.5 \text{ hours}
$$

To express 7.5 hours in hours and minutes:

$$
0.5 \text{ hours} = 30 \text{ minutes}
$$

So,

$$
7.5 \text{ hours} = 7 \text{ hours and } 30 \text{ minutes}
$$

**Answer:**  
It would take Carolyn **7.5 hours** (which is **7 hours and 30 minutes**) to walk 25 miles at the same speed.
**Part (a):** Carolyn's speed was $$ \frac{10}{3} $$ miles per hour, approximately **3.33 mph**. **Part (b):** It would take her **7.5 hours** (7 hours and 30 minutes) to walk 25 miles at the same speed.

4. Carolyn could walk 10 miles in 3 hours. (a) What was her speed? (b) How long would it take her to walk 25 miles at the same speat

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