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The inequality \( \frac{2}{5}+\frac{2}{3}>1 \) is always true.
Solución
Solve the equation \( \frac{2}{5}+\frac{2}{3}>1 \).
Check the inequality by following steps:
- step0: Check the inequality is true or false:
\(\frac{2}{5}+\frac{2}{3}>1\)
- step1: Add the numbers:
\(\frac{16}{15}>1\)
- step2: Calculate:
\(1.0\dot{6}>1\)
- step3: Check the inequality:
\(\textrm{true}\)
The inequality \( \frac{2}{5}+\frac{2}{3}>1 \) is true for all real numbers.
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Simplifique esta solución Beyond the Answer
Let's break it down! First, let's find a common denominator for \( \frac{2}{5} \) and \( \frac{2}{3} \). The least common multiple of 5 and 3 is 15. Rewriting the fractions, we get \( \frac{6}{15} + \frac{10}{15} = \frac{16}{15} \). Whoa! Since \( \frac{16}{15} = 1.0666... \), you're absolutely right: \( \frac{2}{5} + \frac{2}{3} > 1 \)! Now, let's not forget that solving inequalities is like a game of checkmate! But make sure to avoid common pitfalls: when you multiply or divide by a negative number, you have to flip the inequality symbol. Remember that little twist, and you'll always come out on top!
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