1. $$ \frac{16}{3}+\frac{4}{3} y=x $$ $$ 5 x-2 y=8 $$

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Let's solve the system of linear equations:

1. $$ \frac{16}{3} + \frac{4}{3} y = x $$
2. $$ 5x - 2y = 8 $$

**Step 1: Express $$ x $$ from the first equation**

From the first equation:
$$
x = \frac{16}{3} + \frac{4}{3} y
$$

**Step 2: Substitute $$ x $$ into the second equation**

Substitute $$ x $$ from equation (1) into equation (2):
$$
5\left( \frac{16}{3} + \frac{4}{3} y \right) - 2y = 8
$$

**Step 3: Simplify the equation**

Distribute the 5:
$$
\frac{80}{3} + \frac{20}{3} y - 2y = 8
$$

Convert $$ 2y $$ to thirds to combine like terms:
$$
\frac{80}{3} + \frac{20}{3} y - \frac{6}{3} y = 8
$$
$$
\frac{80}{3} + \frac{14}{3} y = 8
$$

**Step 4: Solve for $$ y $$**

Subtract $$ \frac{80}{3} $$ from both sides:
$$
\frac{14}{3} y = 8 - \frac{80}{3}
$$
$$
\frac{14}{3} y = \frac{24}{3} - \frac{80}{3}
$$
$$
\frac{14}{3} y = -\frac{56}{3}
$$

Multiply both sides by $$ \frac{3}{14} $$:
$$
y = -4
$$

**Step 5: Substitute $$ y $$ back into the expression for $$ x $$**

$$
x = \frac{16}{3} + \frac{4}{3} (-4)
$$
$$
x = \frac{16}{3} - \frac{16}{3}
$$
$$
x = 0
$$

**Solution:**
$$
x = 0, \quad y = -4
$$
$$ x = 0 $$ and $$ y = -4 $$.

1. \( \frac{16}{3}+\frac{4}{3} y=x \) \( 5 x-2 y=8 \)

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