Solve for $$ w $$. $$ \frac{w-2}{w+1}+1=\frac{w-2}{w+2} $$ If there is more than one solution, separate them with commas. If there is no solution, click on "No solution".

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Solve the equation $$ \frac{w-2}{w+1}+1=\frac{w-2}{w+2} $$.
Solve the equation by following steps:
- step0: Solve for $$w$$:
  $$\frac{w-2}{w+1}+1=\frac{w-2}{w+2}$$
- step1: Find the domain:
  $$\frac{w-2}{w+1}+1=\frac{w-2}{w+2},w \in \left(-\infty,-2ight)\cup \left(-2,-1ight)\cup \left(-1,+\inftyight)$$
- step2: Multiply both sides of the equation by LCD:
  $$\left(\frac{w-2}{w+1}+1ight)\left(w+1ight)\left(w+2ight)=\frac{w-2}{w+2}	imes \left(w+1ight)\left(w+2ight)$$
- step3: Simplify the equation:
  $$2w^{2}+3w-2=w\left(w+1ight)-2\left(w+1ight)$$
- step4: Calculate:
  $$2w^{2}+3w-2=w^{2}+w-2w-2$$
- step5: Simplify:
  $$2w^{2}+3w-2=w^{2}-w-2$$
- step6: Cancel equal terms:
  $$2w^{2}+3w=w^{2}-w$$
- step7: Move the expression to the left side:
  $$2w^{2}+3w-\left(w^{2}-wight)=0$$
- step8: Calculate:
  $$w^{2}+4w=0$$
- step9: Factor the expression:
  $$w\left(w+4ight)=0$$
- step10: Separate into possible cases:
  $$\begin{align}&w=0\&w+4=0\end{align}$$
- step11: Solve the equation:
  $$\begin{align}&w=0\&w=-4\end{align}$$
- step12: Check if the solution is in the defined range:
  $$\begin{align}&w=0\&w=-4\end{align},w \in \left(-\infty,-2ight)\cup \left(-2,-1ight)\cup \left(-1,+\inftyight)$$
- step13: Find the intersection:
  $$\begin{align}&w=0\&w=-4\end{align}$$
- step14: Rewrite:
  $$w_{1}=-4,w_{2}=0$$
The solutions to the equation $$ \frac{w-2}{w+1}+1=\frac{w-2}{w+2} $$ are $$ w=-4 $$ and $$ w=0 $$.
The solutions are $$ w=-4 $$ and $$ w=0 $$.

Solve for .

If there is more than one solution, separate them with commas.
If there is no solution, click on “No solution”.

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Solve for . If there is more than one solution, separate them with commas. If there is no solution, click on “No solution”.