Use the drawing tools to form the correct answer on the graph. The equations represent functions $$ p $$ and $$ q $$ : $$ p(x)=x-2 $$ $$ q(x)=x+2 $$ The graph of $$ (p \cdot q)(x) $$ is shown. Plot a point at the ordered pair that represents $$ (p \cdot q)(-4) $$ on the graph of the combined function.

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To plot the point $$(p \cdot q)(-4)$$ on the graph of the combined function $$ (p \cdot q)(x) $$, follow these steps:

1. **Calculate $$ (p \cdot q)(-4) $$:**

Given:
   $$
   p(x) = x - 2 \
   q(x) = x + 2
   $$
   
   Compute $$ p(-4) $$ and $$ q(-4) $$:
   $$
   p(-4) = (-4) - 2 = -6 \
   q(-4) = (-4) + 2 = -2
   $$
   
   Now, multiply these results to find $$ (p \cdot q)(-4) $$:
   $$
   (p \cdot q)(-4) = p(-4) \times q(-4) = (-6) \times (-2) = 12
   $$
   
2. **Plot the Point $$(-4, 12)$$ on the Graph:**

- **X-coordinate:** $$-4$$ (Locate this on the horizontal axis).
   - **Y-coordinate:** $$12$$ (Locate this on the vertical axis).
   
   **Visualization:**

Imagine a coordinate plane where:
   - Move 4 units to the **left** of the origin along the x-axis to reach $$-4$$.
   - Move **up** 12 units from the x-axis to reach the y-coordinate $$12$$.
   
   Place a **point** at the intersection of $$-4$$ on the x-axis and $$12$$ on the y-axis.

```
   y
   |
   |                      *
   |                      (-4, 12)
   |
   |________________________ x
          -4
   ```

*(The asterisk $$*$$ represents the plotted point at $$(-4, 12)$$.)*

3. **Confirmation:**

The point $$(-4, 12)$$ lies on the graph of the function $$ (p \cdot q)(x) = x^2 - 4 $$, since:
   $$
   (-4)^2 - 4 = 16 - 4 = 12
   $$
   
   Therefore, the plotted point correctly represents $$ (p \cdot q)(-4) $$.
Plot the point $$(-4, 12)$$ on the graph of the combined function $$ (p \cdot q)(x) $$.

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