Pregunta
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\( \begin{array}{ll}\text { 2. } & x^{2}-7 x+12 \\ \text { 4. } & x^{2}-x-12 \\ \text { 6. } & 5 a^{2}+35 a-40 \\ \text { 8. } & 3 y^{2}+9 y+6 \\ \text { 10. } & 2 x^{2}-24 x+70\end{array} \)

Ask by Ward Mcfarlane. in South Africa
Feb 03,2025

Solución de tutoría real

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Here are the factored forms: 1. \( x^{2}-7x+12 = (x-4)(x-3) \) 2. \( x^{2}-x-12 = (x-4)(x+3) \) 3. \( 5a^{2}+35a-40 = 5(a-1)(a+8) \) 4. \( 3y^{2}+9y+6 = 3(y+1)(y+2) \) 5. \( 2x^{2}-24x+70 = 2(x-7)(x-5) \)

Solución

Factor the expression by following steps: - step0: Factor: \(x^{2}-x-12\) - step1: Rewrite the expression: \(x^{2}+\left(3-4\right)x-12\) - step2: Rewrite the expression: \(x^{2}+3x-4x-12\) - step3: Factor the expression: \(x\left(x+3\right)-4\left(x+3\right)\) - step4: Factor the expression: \(\left(x-4\right)\left(x+3\right)\) Factor the expression \( 3 y^{2}+9 y+6 \). Factor the expression by following steps: - step0: Factor: \(3y^{2}+9y+6\) - step1: Factor the expression: \(3\left(y^{2}+2y+y+2\right)\) - step2: Factor the expression: \(3\left(y\left(y+2\right)+y+2\right)\) - step3: Factor the expression: \(3\left(y+1\right)\left(y+2\right)\) Factor the expression \( x^{2}-7 x+12 \). Factor the expression by following steps: - step0: Factor: \(x^{2}-7x+12\) - step1: Rewrite the expression: \(x^{2}+\left(-3-4\right)x+12\) - step2: Rewrite the expression: \(x^{2}-3x-4x+12\) - step3: Factor the expression: \(x\left(x-3\right)-4\left(x-3\right)\) - step4: Factor the expression: \(\left(x-4\right)\left(x-3\right)\) Factor the expression \( 5 a^{2}+35 a-40 \). Factor the expression by following steps: - step0: Factor: \(5a^{2}+35a-40\) - step1: Factor the expression: \(5\left(a^{2}+8a-a-8\right)\) - step2: Factor the expression: \(5\left(a\left(a+8\right)-\left(a+8\right)\right)\) - step3: Factor the expression: \(5\left(a-1\right)\left(a+8\right)\) Factor the expression \( 2 x^{2}-24 x+70 \). Factor the expression by following steps: - step0: Factor: \(2x^{2}-24x+70\) - step1: Factor the expression: \(2\left(x^{2}-5x-7x+35\right)\) - step2: Factor the expression: \(2\left(x\left(x-5\right)-7\left(x-5\right)\right)\) - step3: Factor the expression: \(2\left(x-7\right)\left(x-5\right)\) Here are the factored forms of the given expressions: 1. For \( x^{2}-7x+12 \): \[ x^{2}-7x+12 = (x-4)(x-3) \] 2. For \( x^{2}-x-12 \): \[ x^{2}-x-12 = (x-4)(x+3) \] 3. For \( 5a^{2}+35a-40 \): \[ 5a^{2}+35a-40 = 5(a-1)(a+8) \] 4. For \( 3y^{2}+9y+6 \): \[ 3y^{2}+9y+6 = 3(y+1)(y+2) \] 5. For \( 2x^{2}-24x+70 \): \[ 2x^{2}-24x+70 = 2(x-7)(x-5) \] If you need further assistance or explanations, feel free to ask!

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Beyond the Answer

Did you know that quadratic equations, like the ones you've listed, have been studied for thousands of years? Ancient mathematicians, including those from Babylon and Greece, were already solving these types of equations, albeit using different methods! They pioneered methods that laid the groundwork for the modern quadratic formula we use today, showcasing the timeless nature of solving these mathematical puzzles. In the real world, quadratic equations are everywhere! They help us in fields ranging from engineering to economics. For instance, they can model the trajectory of a projectile in physics or help businesses find maximum profit given certain constraints. Understanding how to factor or apply the quadratic formula can make a huge difference when analyzing these scenarios—it’s like having a toolkit for tackling real-life challenges!

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