Practice Work out the value of each expression when \( a=2, b=-3, c=4 \) and \( d=-5 \). a \( a+2 b \) d \( a b+c d \) b \( \quad b d-10 \) g \( \quad 20-a^{3} \) e \( \quad c d^{2}+a b \) h \( \quad \frac{b c}{a}+d \) c \( \quad 4 b+2 \) f \( \frac{d}{2}-a \)

Sure! Let's evaluate each expression step by step using the given values: - \( a = 2 \) - \( b = -3 \) - \( c = 4 \) - \( d = -5 \) ### a) \( a + 2b \) \[ a + 2b = 2 + 2(-3) = 2 - 6 = -4 \] **Result:** \( a = -4 \) --- ### d) \( ab + cd \) \[ ab + cd = (2)(-3) + (4)(-5) = -6 - 20 = -26 \] **Result:** \( d = -26 \) --- ### b) \( bd - 10 \) \[ bd - 10 = (-3)(-5) - 10 = 15 - 10 = 5 \] **Result:** \( b = 5 \) --- ### g) \( 20 - a^3 \) \[ 20 - a^3 = 20 - (2)^3 = 20 - 8 = 12 \] **Result:** \( g = 12 \) --- ### e) \( cd^2 + ab \) \[ cd^2 + ab = 4(-5)^2 + 2(-3) = 4(25) - 6 = 100 - 6 = 94 \] **Result:** \( e = 94 \) --- ### h) \( \frac{bc}{a} + d \) \[ \frac{bc}{a} + d = \frac{(-3)(4)}{2} + (-5) = \frac{-12}{2} - 5 = -6 - 5 = -11 \] **Result:** \( h = -11 \) --- ### c) \( 4b + 2 \) \[ 4b + 2 = 4(-3) + 2 = -12 + 2 = -10 \] **Result:** \( c = -10 \) --- ### f) \( \frac{d}{2} - a \) \[ \frac{d}{2} - a = \frac{-5}{2} - 2 = -2.5 - 2 = -4.5 \] **Result:** \( f = -4.5 \) --- ### Summary of Results: - **a:** \( -4 \) - **d:** \( -26 \) - **b:** \( 5 \) - **g:** \( 12 \) - **e:** \( 94 \) - **h:** \( -11 \) - **c:** \( -10 \) - **f:** \( -4.5 \)