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Aufgabe: (2 Punkte) Gegeben ist die Ebene \( \mathrm{E}:-3 x_{2}-4 x_{3}=24 \). Bestimme die Gleichung einer Ebene \( F \), die parallel zu E ist und den Abstand \( \mathrm{d}=10 \mathrm{zu} \mathrm{E} \) hat. \( \mathrm{F}:+\hat{v} \square \mathrm{x}_{1}+\hat{v} \) Bitte nur ganzzahlige Koordinaten für die Vektoren eingeben. Ich möchte nur die Lösung sehen

Ask by Williams Morgan. in Germany
Feb 03,2025

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The equation of the plane \( F \) is: \[ -3x_{2} - 4x_{3} = 74 \]

Solución

Eine mögliche Gleichung der Ebene \( F \) ist: \[ -3\,x_{2} - 4\,x_{3} = 74 \]

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Die Gleichung der gesuchten Ebene \( F \) ist \( F: -3 x_{2} - 4 x_{3} = 14 \).

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