Pregunta
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1.2 If , for which values of is

Ask by Pierce Spencer. in South Africa
Jan 03,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

  • Non-Real:
  • Undefined: and
  • Positive: excluding

Solución

Let’s analyze the function to determine the conditions for each part of the problem.

1.2.2 Values of for which is Non-Real

For to be real, the expression under the square root must be non-negative:
Therefore, is non-real when:

1.2.3 Values of for which is Undefined

The function is undefined when the denominator is zero:
Therefore, is undefined at:

1.2.4 Values of for which

For to be positive:
  1. The square root must be positive, which requires:
  2. The denominator must be positive:
Combining these two conditions:
However, we must exclude and because the function is undefined at these points. Since is already excluded by , we only need to exclude .
Therefore, for:

Summary of Results

  1. Non-Real Values:
  2. Undefined Values: and
  3. Positive Values: with

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Beyond the Answer

To determine when is non-real, we need to focus on the square root in the numerator. The expression under the square root, , must be non-negative. Thus, leads to . If , will be non-real since the square root of a negative number isn’t defined in the reals.
For to be undefined, we look at the denominator . Setting this equal to zero gives , which simplifies to , leading to possible undefined points at and . Therefore, is undefined at these two values.
To find when , both the numerator and the denominator must be positive. The numerator when (i.e., ). The denominator simplifies to or . Combining these conditions, is where . Thus, all intervals where is positive are between and excluding where it becomes undefined.

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