The equation \( z^{2}+y^{2}-(\tan (x))^{2}=0 \) represents a surface of revolution. Around which axis was the profile curve revolved to generate this equation? \( x \)-axis \( y \)-axis Write the equation of the profile curve in the \( x z \)-plane.
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To determine around which axis the profile curve was revolved, let's rearrange the given equation: \[ z^2 + y^2 = (\tan(x))^2 \] This form suggests that for a fixed value of \( y \) (where \( y \) can be between positive and negative values), the equation describes a circle in the \( xz \)-plane. This indicates that the profile curve representing \( z \) and \( x \) must have been revolved around the \( y \)-axis to generate the surface of revolution. Now, in the \( xz \)-plane, by letting \( y = 0 \), the profile curve is given as: \[ z^2 = (\tan(x))^2 \] Taking the positive and negative roots, we get: \[ z = \tan(x) \quad \text{and} \quad z = -\tan(x) \] Thus, the equation of the profile curve in the \( xz \)-plane is \( z = \pm\tan(x) \).