Add. Simplify, if possible. \( \frac{6}{y^{2}+18 y+81}+\frac{3}{y^{2}-81} \)
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To simplify the given expression, start by factoring the denominators. The first denominator \( y^2 + 18y + 81 \) factors into \( (y + 9)^2 \), while the second denominator \( y^2 - 81 \) is a difference of squares and factors into \( (y - 9)(y + 9) \). Now we can rewrite the expression: \[ \frac{6}{(y + 9)^2} + \frac{3}{(y - 9)(y + 9)} \] Next, find a common denominator, which is \( (y + 9)^2(y - 9) \). Now rewrite each fraction with the common denominator: \[ \frac{6(y - 9)}{(y + 9)^2(y - 9)} + \frac{3(y + 9)}{(y - 9)(y + 9)(y + 9)} \] This simplifies to: \[ \frac{6(y - 9) + 3(y + 9)}{(y + 9)^2(y - 9)} \] Now combine the numerators: \[ 6y - 54 + 3y + 27 = 9y - 27 \] Thus, the expression is now: \[ \frac{9y - 27}{(y + 9)^2(y - 9)} \] Now, we can factor out a 9 from the numerator: \[ \frac{9(y - 3)}{(y + 9)^2(y - 9)} \] So the simplified form of the expression is: \[ \frac{9(y - 3)}{(y + 9)^2(y - 9)} \]