d) \( \lim _{x-1} s x^{2}-3 x+1 \)

To solve the limit as \( x \) approaches 1, we substitute \( x = 1 \) directly into the expression \( sx^2 - 3x + 1 \): \[ s(1)^2 - 3(1) + 1 = s - 3 + 1 = s - 2 \] Thus, \( \lim_{x \to 1} (sx^2 - 3x + 1) = s - 2 \). So, the answer is \( s - 2 \).