8. Circle the name of any student who wrote o quadratio funclion with zeros at 2 and -5 . KINA MILTON \( y=x^{2}+3 x-10 \) \( y=4 x^{2}-3 x-10 \)

To determine which student wrote a quadratic function with zeros at \( x = 2 \) and \( x = -5 \), let's analyze each function provided: 1. **KINA**: \( y = x^{2} + 3x - 10 \) - To find the zeros, set \( y = 0 \): \[ x^{2} + 3x - 10 = 0 \] - Using the quadratic formula: \[ x = \frac{-3 \pm \sqrt{9 + 40}}{2} = \frac{-3 \pm 7}{2} \] - Solutions: - \( x = \frac{4}{2} = 2 \) - \( x = \frac{-10}{2} = -5 \) **Zeros:** \( x = 2 \) and \( x = -5 \) 2. **MILTON**: \( y = 4x^{2} - 3x - 10 \) - To find the zeros, set \( y = 0 \): \[ 4x^{2} - 3x - 10 = 0 \] - Using the quadratic formula: \[ x = \frac{3 \pm \sqrt{9 + 160}}{8} = \frac{3 \pm 13}{8} \] - Solutions: - \( x = \frac{16}{8} = 2 \) - \( x = \frac{-10}{8} = -1.25 \) **Zeros:** \( x = 2 \) and \( x = -1.25 \) **Conclusion:** Only **KINA's** quadratic function has the zeros at \( x = 2 \) and \( x = -5 \). Therefore, you should **circle the name KINA**.