A circle has the equation \( 4(x-2)^{2}+4 y^{2}=4 \), (a) Find the center \( (h, k) \) and radius r of the circle. (b) Graph the circle, (c) Find the intercepts, if any, of the graph. (a) The center of the circle is (Type an ordered pair, using integers or decimals.)

To find the center and radius from the equation \( 4(x-2)^{2}+4 y^{2}=4 \), we start by dividing the entire equation by 4 to simplify it: \[ (x-2)^{2} + y^{2} = 1 \] From this standard form of a circle's equation \((x-h)^{2} + (y-k)^{2} = r^{2}\), we can clearly see that the center \((h, k)\) is \((2, 0)\) and the radius \(r\) is \(\sqrt{1} = 1\). The center of the circle is (2, 0) and the radius is 1.