On the moon, the equation $$ d=0.8 t^{2} $$ is used to find the distance an object has fallen after $$ t $$ seconds. On Earth, the equation is $$ d=4.9 t^{2} $$. A rock is thrown from a height of 60 meters on Earth. Plot the graph of the equation on a graphing calculator or other technology to find the time taken to the ground to the nearest second. $$ t= $$ Enter your next step here s

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To determine the time it takes for the rock to reach the ground, follow these steps:

1. **Set Up the Equation:**
   
   The distance $$ d $$ fallen is given by the equation:
   $$
   d = 4.9 t^{2}
   $$
   
   Since the rock is thrown from a height of 60 meters, set $$ d = 60 $$ meters:
   $$
   60 = 4.9 t^{2}
   $$

2. **Solve for $$ t $$:**
   
   Divide both sides by 4.9 to isolate $$ t^{2} $$:
   $$
   t^{2} = \frac{60}{4.9} \approx 12.2449
   $$
   
   Take the square root of both sides to find $$ t $$:
   $$
   t \approx \sqrt{12.2449} \approx 3.5 \text{ seconds}
   $$

3. **Round to the Nearest Second:**
   
   Rounding 3.5 seconds to the nearest whole number gives:
   $$
   t \approx 4 \text{ seconds}
   $$

**Answer:**  
$$ t = 4 $$ seconds
$$ t = 4 $$ seconds

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