9) \( \begin{array}{l}-5 x+y=-2 \\ -3 x+6 y=-12\end{array} \)

Solve the system of equations \( -5x+y=-2;-3x+6y=-12 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}-5x+y=-2\\-3x+6y=-12\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}y=-2+5x\\-3x+6y=-12\end{array}\right.\) - step2: Substitute the value of \(y:\) \(-3x+6\left(-2+5x\right)=-12\) - step3: Simplify: \(27x-12=-12\) - step4: Move the constant to the right side: \(27x=-12+12\) - step5: Add the numbers: \(27x=0\) - step6: Rewrite the expression: \(x=0\) - step7: Substitute the value of \(x:\) \(y=-2+5\times 0\) - step8: Simplify: \(y=-2\) - step9: Calculate: \(\left\{ \begin{array}{l}x=0\\y=-2\end{array}\right.\) - step10: Check the solution: \(\left\{ \begin{array}{l}x=0\\y=-2\end{array}\right.\) - step11: Rewrite: \(\left(x,y\right) = \left(0,-2\right)\) The solution to the system of equations is \( (x, y) = (0, -2) \).