(1) Factor completely: \( 6 x+24 \) (2) Factor completely: \( 6 x^{2}+11 x-10 \)

Let's dive into the factoring fun! To tackle \( 6x + 24 \), first, let's spot the common factor. Both terms have a 6 in common, so we factor that out, giving us \( 6(x + 4) \). Voila! We've transformed it into a simpler expression by spotting that common factor! Now, for \( 6x^2 + 11x - 10 \), we can use the "ac method" to factor this quadratic expression. First, multiply \( a \) and \( c\) (6 and -10), which gives us -60. We need two numbers that multiply to -60 and add to 11. Those numbers are 15 and -4. Rewrite the expression as \( 6x^2 + 15x - 4x - 10 \), then group terms: \( 3x(2x + 5) - 2(2x + 5) \). Factoring by grouping, we get \( (2x + 5)(3x - 2) \). Super cool, right?