Find the solution of the system of equations. \[ \begin{aligned}-10 x-y & =-29 \\ 10 x+7 y & =23\end{aligned} \]
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To solve the system of equations, we can use the method of substitution or elimination. Here, we'll use elimination. First, let's write down the equations: 1. \( -10x - y = -29 \) (Equation 1) 2. \( 10x + 7y = 23 \) (Equation 2) We'll rearrange Equation 1 to express \( y \) in terms of \( x \): \[ y = -10x + 29 \] Now, we'll substitute this expression for \( y \) into Equation 2: \[ 10x + 7(-10x + 29) = 23 \] Expanding this gives: \[ 10x - 70x + 203 = 23 \] Simplifying it further: \[ -60x + 203 = 23 \] Now, we'll isolate \( x \): \[ -60x = 23 - 203 \] \[ -60x = -180 \] \[ x = 3 \] Now that we have \( x \), we can substitute it back into the equation for \( y \): \[ y = -10(3) + 29 \] \[ y = -30 + 29 \] \[ y = -1 \] Thus, the solution of the system of equations is: \[ (x, y) = (3, -1) \]