Use the four-step process to find $$ s^{\prime}(x) $$ and then find $$ s^{\prime}(1), s^{\prime}(2) $$, and $$ s^{\prime}(3) $$ $$ s(x)=9 x-5 $$ $$ s^{\prime}(x)=\square $$ (Simplify your answer. Use inlegers or fractions for any numbers in the expression.) $$ s^{\prime}(1)=\square $$ (Type an integer or a simplified fraction.) $$ s^{\prime}(2)=\square $$ (Type an integer or a simplified fraction.) $$ s^{\prime}(3)=\square $$ (Type an integer or a simplified fraction.)

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To find the derivative $$ s^{\prime}(x) $$ of the function $$ s(x) = 9x - 5 $$ and evaluate it at $$ x = 1 $$, $$ x = 2 $$, and $$ x = 3 $$, we can use the **four-step process for finding derivatives**. Here's how it's done:

### Step 1: Write Down the Function
$$ s(x) = 9x - 5 $$

### Step 2: Apply the Definition of the Derivative
The derivative $$ s^{\prime}(x) $$ is defined as:
$$ s^{\prime}(x) = \lim_{h \to 0} \frac{s(x + h) - s(x)}{h} $$

### Step 3: Substitute and Simplify
1. **Find $$ s(x + h) $$:**
   $$ s(x + h) = 9(x + h) - 5 = 9x + 9h - 5 $$

2. **Compute $$ s(x + h) - s(x) $$:**
   $$ s(x + h) - s(x) = (9x + 9h - 5) - (9x - 5) = 9h $$

3. **Form the Difference Quotient:**
   $$ \frac{s(x + h) - s(x)}{h} = \frac{9h}{h} = 9 $$

### Step 4: Take the Limit as $$ h \to 0 $$
$$ s^{\prime}(x) = \lim_{h \to 0} 9 = 9 $$

So, the derivative is:
$$ s^{\prime}(x) = 9 $$

### Evaluating the Derivative at Specific Points
Since $$ s^{\prime}(x) = 9 $$ is a constant, it doesn't depend on $$ x $$. Therefore:

1. **At $$ x = 1 $$:**
   $$ s^{\prime}(1) = 9 $$

2. **At $$ x = 2 $$:**
   $$ s^{\prime}(2) = 9 $$

3. **At $$ x = 3 $$:**
   $$ s^{\prime}(3) = 9 $$

### Summary of Answers
- $$ s^{\prime}(x) = 9 $$
- $$ s^{\prime}(1) = 9 $$
- $$ s^{\prime}(2) = 9 $$
- $$ s^{\prime}(3) = 9 $$
$$ s^{\prime}(x) = 9 $$, $$ s^{\prime}(1) = 9 $$, $$ s^{\prime}(2) = 9 $$, $$ s^{\prime}(3) = 9 $$.

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