Given the function $$ g(x)=4 x^{3}-18 x^{2}+24 x $$, find the first derivative, $$ g^{\prime}(x) $$. $$ g^{\prime}(x)=\square $$

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Find the first order derivative with respect to $$ x $$ for $$ 4x^3-18x^2+24x $$.
Evaluate the derivative by following steps:
- step0: Evaluate the derivative:
  $$\frac{d}{dx}\left(4x^{3}-18x^{2}+24x\right)$$
- step1: Use differentiation rules:
  $$\frac{d}{dx}\left(4x^{3}\right)-\frac{d}{dx}\left(18x^{2}\right)+\frac{d}{dx}\left(24x\right)$$
- step2: Calculate:
  $$12x^{2}-36x+24$$
The first derivative of the function $$ g(x) = 4x^{3} - 18x^{2} + 24x $$ is $$ g'(x) = 12x^{2} - 36x + 24 $$.
$$ g^{\prime}(x) = 12x^{2} - 36x + 24 $$

Given the function , find
the first derivative, .

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