Which situation below correctly represents the algebraic expression \( 6 x-2 \) ? (A) Tom has 6 children he is taking to the zoo and 2 children decided not to go. OB) Tom bought 6 tickets to enter the zoo and he had a coupon for 2 dollars off the price. O C) Tom brought enough lunches for six children and he had two left over.

Let's analyze each option to determine which correctly represents the algebraic expression \( 6x - 2 \). ### Option A: **"Tom has 6 children he is taking to the zoo and 2 children decided not to go."** - **Interpretation:** If Tom initially planned to take 6 children and 2 decided not to go, the number of children going would be \( 6 - 2 = 4 \). - **Algebraic Representation:** This situation is best represented by \( 6 - 2 \), not \( 6x - 2 \). ### Option B: **"Tom bought 6 tickets to enter the zoo and he had a coupon for 2 dollars off the price."** - **Interpretation:** Let \( x \) represent the cost of one ticket. The total cost for 6 tickets would be \( 6x \). With a coupon for 2 dollars off, the total cost becomes \( 6x - 2 \). - **Algebraic Representation:** This directly matches \( 6x - 2 \). ### Option C: **"Tom brought enough lunches for six children and he had two left over."** - **Interpretation:** If Tom brought lunches for 6 children and had 2 left, the number of children who ate lunch is \( 6x - 2 \) where \( x \) could represent some factor related to lunch consumption. - **Algebraic Representation:** While this could be represented by \( 6x - 2 \), the connection is less direct compared to Option B. ### **Conclusion:** **Option B** accurately represents the algebraic expression \( 6x - 2 \) because it directly correlates the total cost of 6 tickets with the subtraction of a 2-dollar coupon. **Answer:** Option B. Tom bought 6 tickets to enter the zoo and he had a coupon for 2 dollars off the price.