n official major league baseball has a mass of 0.14 kg . A pitcher throws a 40 \( / \mathrm{s} \) fastball which is hit by the batter straight back up the middle at a speed of \( 6 \mathrm{~m} / \mathrm{s} \).

To solve this problem, we need to calculate the momentum of the baseball before and after it is hit by the batter. Given: - Mass of the baseball: \( m = 0.14 \, \text{kg} \) - Initial speed of the fastball: \( v_i = 40 \, \text{m/s} \) - Speed of the baseball after being hit: \( v_f = 6 \, \text{m/s} \) The momentum of an object is given by the formula: \[ p = m \times v \] Let's calculate the momentum of the baseball before and after it is hit by the batter. Calculate the value by following steps: - step0: Calculate: \(0.14\times 40\) - step1: Multiply the numbers: \(5.6\) The momentum of the baseball before it is hit by the batter is \( p_i = 5.6 \, \text{kg m/s} \). Now, let's calculate the momentum of the baseball after it is hit by the batter. Calculate the value by following steps: - step0: Calculate: \(0.14\times 6\) - step1: Multiply the numbers: \(0.84\) The momentum of the baseball after it is hit by the batter is \( p_f = 0.84 \, \text{kg m/s} \). Therefore, the change in momentum of the baseball after being hit by the batter is \( \Delta p = p_f - p_i = 0.84 \, \text{kg m/s} - 5.6 \, \text{kg m/s} = -4.76 \, \text{kg m/s} \).