dhe equation of the axis of symmetry of the following parabola algebraically. $$ y=-3 x^{2}+24 x-66 $$ Answer Attempt 1 out of 2

Question

UpStudy AI · Accepted Answer

To find the **axis of symmetry** of the parabola given by the quadratic equation:

$$
y = -3x^{2} + 24x - 66
$$

we can use the formula for the axis of symmetry of a parabola in the form $$ y = ax^{2} + bx + c $$:

$$
x = -\frac{b}{2a}
$$

**Step-by-Step Solution:**

1. **Identify the coefficients** $$ a $$, $$ b $$, and $$ c $$:
   $$
   a = -3,\quad b = 24,\quad c = -66
   $$

2. **Apply the axis of symmetry formula**:
   $$
   x = -\frac{b}{2a} = -\frac{24}{2(-3)} = -\frac{24}{-6} = 4
   $$

3. **Write the equation of the axis of symmetry**:
   $$
   \boxed{x = 4}
   $$

**Conclusion:**
The axis of symmetry for the given parabola is the vertical line where $$ x = 4 $$.
The axis of symmetry is $$ x = 4 $$.

dhe equation of the axis of symmetry of the following parabola algebraically. \[ y=-3 x^{2}+24 x-66 \] Answer Attempt 1 out of 2