To balance the equation, we start with the unbalanced form:

First, we see that there are 2 oxygen atoms on the reactant side (from SnO2) and only 1 on the product side (in H2O). Hence, we need to add a coefficient of 2 in front of H2O:

Now, we have 2 hydrogen atoms in H2O, thus we will add a coefficient of 2 to H2:

Now let’s count again: we have 1 Sn, 2 O, and 4 H on the reactant side, and we have 1 Sn, 2 O, and 4 H on the product side. The equation is balanced!

So, the balanced equation looks like this: