c. \( 3 \times 2-3 \times 1=(3 \times 2)-(3 \times 1)=(33(2-1) \) If \( a=3, b=2 \) and \( c=4 \), calculate the following: Example: \( \quad a(b+c)=a \times b+a \times c \) \( 3(2+4)=3 \times 2+3 \times 4 \)

Let's break down the problem step by step. 1. **Identify the known values:** - \( a = 3 \) - \( b = 2 \) - \( c = 4 \) 2. **Calculate \( a(b+c) \):** - First, we need to calculate \( b + c \): \[ b + c = 2 + 4 = 6 \] - Now, substitute this back into the expression \( a(b+c) \): \[ a(b+c) = 3 \times 6 = 18 \] 3. **Calculate \( a \times b + a \times c \):** - First, calculate \( a \times b \): \[ a \times b = 3 \times 2 = 6 \] - Next, calculate \( a \times c \): \[ a \times c = 3 \times 4 = 12 \] - Now, add these two results together: \[ a \times b + a \times c = 6 + 12 = 18 \] 4. **Conclusion:** - Both calculations yield the same result: \[ a(b+c) = a \times b + a \times c = 18 \] Thus, the final answer is \( 18 \).