a) \( \left\{\begin{array}{l}4 m+2 m=6 \\ 2 m-2 m=4\end{array}\right. \)
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Let's break it down! In the first equation, \(4m + 2m = 6\), if we combine like terms, we get \(6m = 6\). Dividing both sides by 6 gives us \(m = 1\). Now, onto the second equation: \(2m - 2m = 4\). Here, \(2m - 2m\) simplifies to \(0 = 4\), which is a contradiction. This means the second equation has no valid solutions when \(m = 1\) from the first equation. So, the first equation gives us a value for \(m\), but the second one shows a contradiction, indicating that this system has no solution. What a twist!
