Let \( A=\left\{-9,-\frac{12}{4},-\frac{5}{8},-\sqrt{5}, 0, \frac{1}{4}, 5,6 \pi, 3, \sqrt{12}\right\} \). List all the elements of \( A \) that belong to the set of integers.

To determine which elements of the set \( A = \left\{-9, -\frac{12}{4}, -\frac{5}{8}, -\sqrt{5}, 0, \frac{1}{4}, 5, 6\pi, 3, \sqrt{12}\right\} \) are integers, let's evaluate each element: 1. **\(-9\)**: This is an integer. 2. **\(-\frac{12}{4}\)**: Simplifies to \(-3\), which is an integer. 3. **\(-\frac{5}{8}\)**: This is a fraction and not an integer. 4. **\(-\sqrt{5}\)**: An irrational number, not an integer. 5. **\(0\)**: This is an integer. 6. **\(\frac{1}{4}\)**: This is a fraction, not an integer. 7. **\(5\)**: This is an integer. 8. **\(6\pi\)**: Since \(\pi\) is irrational, \(6\pi\) is also irrational and not an integer. 9. **\(3\)**: This is an integer. 10. **\(\sqrt{12}\)**: Simplifies to \(2\sqrt{3}\), which is irrational and not an integer. **In summary, the integers in set \( A \) are:** \[ -9, -3, 0, 3, 5 \] **Final Answer:** All integer elements of \( A \) are –9, –3, 0, 3, and 5.