\( \left\{ \begin{array} { l } { y = - 6 } \\ { x = - 4 y - 5 } \end{array} \left\{ \begin{array} { l } { x = \square } \end{array} \right. \right. \)

Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}y=-6\\x=-4y-5\end{array}\right.\) - step1: Substitute the value of \(y:\) \(x=-4\left(-6\right)-5\) - step2: Simplify: \(x=19\) - step3: Calculate: \(\left\{ \begin{array}{l}x=19\\y=-6\end{array}\right.\) - step4: Check the solution: \(\left\{ \begin{array}{l}x=19\\y=-6\end{array}\right.\) - step5: Rewrite: \(\left(x,y\right) = \left(19,-6\right)\) To solve the system of equations: 1. **First Equation:** \( y = -6 \) 2. **Second Equation:** \( x = -4y - 5 \) We can substitute the value of \( y \) from the first equation into the second equation. ### Step 1: Substitute \( y \) Substituting \( y = -6 \) into the second equation: \[ x = -4(-6) - 5 \] ### Step 2: Calculate \( x \) Now, calculate \( x \): \[ x = 24 - 5 = 19 \] ### Final Solution Thus, the solution to the system of equations is: \[ (x, y) = (19, -6) \] So, \( x = 19 \) and \( y = -6 \).