Solve the following equation by the square root method. \[ (4 y+6)^{2}=36 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is \( \{\square\} \). (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. There nolution.

Solve the equation \( (4y+6)^2=36 \). Solve the quadratic equation by following steps: - step0: Solve using square roots: \(\left(4y+6\right)^{2}=36\) - step1: Simplify the expression: \(4y+6=\pm \sqrt{36}\) - step2: Simplify the expression: \(4y+6=\pm 6\) - step3: Separate into possible cases: \(\begin{align}&4y+6=6\\&4y+6=-6\end{align}\) - step4: Solve the equation: \(\begin{align}&y=0\\&y=-3\end{align}\) - step5: Rewrite: \(y_{1}=-3,y_{2}=0\) The solutions to the equation \((4y+6)^2=36\) are \(y=-3\) and \(y=0\). Therefore, the correct choice is: A. The solution set is \(\{-3, 0\}\).