Suppose that the functions \( q \) and \( r \) are defined as follows. \[ \begin{array}{l}q(x)=-2 x \\ r(x)=2 x^{2}-1 \\ \text { Find the following. } \\ (r \circ q)(-1)=7 \\ (q \circ r)(-1)=\square\end{array} \]

To find \((q \circ r)(-1)\), we first need to evaluate \(r(-1)\) and then apply the function \(q\) to the result. 1. **Calculate \(r(-1)\):** \[ r(x) = 2x^2 - 1 \] \[ r(-1) = 2(-1)^2 - 1 = 2(1) - 1 = 2 - 1 = 1 \] 2. **Apply \(q\) to the result of \(r(-1)\):** \[ q(x) = -2x \] \[ q(r(-1)) = q(1) = -2(1) = -2 \] Therefore, \((q \circ r)(-1) = -2\). **Answer:** \(-2\)